We need the balanced chemical equation for the reaction between copper and copper II oxide:
Cu + CuO → 2 CuO
From the equation, we see that 1 mole of copper reacts with 1 mole of copper II oxide to produce 2 moles of copper II oxide. We can use this information to set up a proportion:
1 mole Cu / 1 mole CuO = 2 moles CuO / x moles CuO
Solving for x, we get:
x = 2 moles CuO
Now we can use the molar mass of copper II oxide to convert moles to grams:
2 moles CuO x 79.55 g/mol = 159.1 g CuO
Therefore, 159.1 grams of copper II oxide will be formed when 125 grams of copper reacts.
What mass grams of copper II oxide will be formed if 125 grams of copper reacts?
1 answer