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What linear speed must a 4.0×10−2kg hula hoop have if its total kinetic energy is to be 0.20J ? Assume the hoop rolls on the ground without slipping.

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KE(total)= KE(transl) +KE(rot) =
=mv²/2 +Iω²/2=
=mv²/2 +(mR²)v²/2R²=mv²
v= sqrt{KE/m)=sqrt(0.2/0.04) =0.5 m/s

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