What length pendulum will produce a period of 1.0s?

Answer 1

t = 2p1*sqrt(l/g),
t^2 = 4 * (pi)^2 * l/g.

t in seconds.

l in meters or cm.

g = acceleration due to gravity:
9.8 m/s^2 or 980 cm/s^2.

NOTE: l and g should both be in m/s^2
or cm/s^2.

t^2 = 4 * 9.87 * l/9.8 = 1^2,
39.48l / 9.8 = 1,
4.03l = 1,
l = 1 / 4.03 = 0.248 m = 24.8 cm.