What is wrong with the following code? Scanner input = new Scanner(System.in); String s = nextLine(); Group of answer choices Should be: String s = input.nextLine(); Nothing is wrong, that code won't generate any errors. Should be: String s = input.next; nextLine() method can't work with String variables Should be: String s = next();

Answer 1

The issue with the code you provided is in the way the nextLine() method is called. Specifically, the correct way to call nextLine() is on the input object, which is an instance of the Scanner class.

Here is the correct line of code:

String s = input.nextLine();

This means the correct choice from the options you provided would be:

Should be: String s = input.nextLine();

The other options are incorrect for the following reasons:

• "Nothing is wrong, that code won't generate any errors." - This is incorrect because the code as written will result in a compilation error since nextLine() is not being called on the Scanner object.

• "Should be: String s = input.next;" - This is incorrect. The next() method reads the next token (word) rather than a full line, and it's not the correct method to call.

• "nextLine() method can't work with String variables" - This statement is misleading. The nextLine() method returns a String, and it can indeed be assigned to a String variable.

So, the correct answer is that the code should be modified to call nextLine() on the input object.