What is the width of a rectangle with a length of 6/7 feet and an area of 5 square feet?

1 answer

To find the width of a rectangle given its length and area, you can use the formula for the area of a rectangle:

\[ \text{Area} = \text{Length} \times \text{Width} \]

In this case, you are given:

  • Length = \( \frac{6}{7} \) feet
  • Area = 5 square feet

Let \( W \) represent the width of the rectangle. We can rearrange the area formula to solve for the width:

\[ W = \frac{\text{Area}}{\text{Length}} \]

Substituting the values we have:

\[ W = \frac{5 \text{ square feet}}{\frac{6}{7} \text{ feet}} \]

To divide by a fraction, you multiply by its reciprocal:

\[ W = 5 \text{ square feet} \times \frac{7}{6} \text{ feet}^{-1} \]

Calculating this gives:

\[ W = \frac{5 \times 7}{6} = \frac{35}{6} \]

Thus,

\[ W = \frac{35}{6} \text{ feet} \]

Converting \( \frac{35}{6} \) to a mixed number, we find that:

\[ \frac{35}{6} = 5 \frac{5}{6} \]

Therefore, the width of the rectangle is

\[ \frac{35}{6} \text{ feet} \quad \text{or} \quad 5 \frac{5}{6} \text{ feet}. \]