mL1 x M1 = mL2 x M2
20 x 0.1 = mL2 x 0.02
Solve for mL2 which gives you the FINAL volume. Subtract the final - initial to find amount to be added. Technically, that will not be right since volumes are not additive but for dilute solutions like this the difference is minuscule.
what is the volume that must be added to dillute 20.0 ml of 0.1M Hcl to 0.02M Hcl
1 answer
1 answer