What is the volume of the pyramid? h=11 w=7 l=10

Answer 1

To find the volume of a pyramid, you can use the formula:

\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

For a rectangular pyramid, the base area can be calculated as:

\[ \text{Base Area} = \text{width} \times \text{length} = w \times l \]

In this case, you provided \( h = 11 \), \( w = 7 \), and \( l = 10 \).

First, calculate the base area:

\[ \text{Base Area} = 7 \times 10 = 70 \]

Now plug this into the volume formula:

\[ \text{Volume} = \frac{1}{3} \times 70 \times 11 \] \[ \text{Volume} = \frac{1}{3} \times 770 \] \[ \text{Volume} = \frac{770}{3} \approx 256.67 \]

So, the volume of the pyramid is approximately \( 256.67 \) cubic units.

Answer 2

What is the volume of the pyramid in cubic feet? h=20 l=24 w=15

Answer 3

To find the volume of a pyramid, you can use the formula:

\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

For a rectangular pyramid, the base area is given by:

\[ \text{Base Area} = w \times l \]

Given \( h = 20 \) feet, \( w = 15 \) feet, and \( l = 24 \) feet, let's calculate the base area first:

\[ \text{Base Area} = 15 \times 24 = 360 \text{ square feet} \]

Now, plug this into the volume formula:

\[ \text{Volume} = \frac{1}{3} \times 360 \times 20 \] \[ \text{Volume} = \frac{7200}{3} \] \[ \text{Volume} = 2400 \text{ cubic feet} \]

Thus, the volume of the pyramid is 2400 cubic feet.

Answer 4

A right rectangular pyramid has an altitude of 22.3 inches, a length of 6.75 inches, and a width of 10.25 inches. What is the volume of the pyramid in cubic inches?

Answer 5

To find the volume of a right rectangular pyramid, you can use the formula:

\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

For a rectangular pyramid, the base area is given by:

\[ \text{Base Area} = \text{length} \times \text{width} = l \times w \]

Given:

• Height (\( h \)) = 22.3 inches
• Length (\( l \)) = 6.75 inches
• Width (\( w \)) = 10.25 inches

First, calculate the base area:

\[ \text{Base Area} = 6.75 \times 10.25 = 69.1875 \text{ square inches} \]

Now plug this into the volume formula:

\[ \text{Volume} = \frac{1}{3} \times 69.1875 \times 22.3 \] \[ \text{Volume} = \frac{1}{3} \times 1547.1875 \approx 515.7292 \]

Thus, the volume of the pyramid is approximately 515.73 cubic inches.

Answer 6

try again

Answer 7

Let's recalculate the volume of the right rectangular pyramid step by step, ensuring accuracy.

The formula for the volume \( V \) of a pyramid is:

\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]

Given:

• Height (\( h \)) = 22.3 inches
• Length (\( l \)) = 6.75 inches
• Width (\( w \)) = 10.25 inches

Step 1: Calculate the Base Area

The base area \( A \) of the pyramid is calculated as:

\[ \text{Base Area} = l \times w = 6.75 \times 10.25 \]

Calculating this:

\[ \text{Base Area} = 6.75 \times 10.25 = 69.1875 \text{ square inches} \]

Step 2: Calculate the Volume

Now, use the base area to calculate the volume:

\[ V = \frac{1}{3} \times \text{Base Area} \times h \] \[ V = \frac{1}{3} \times 69.1875 \times 22.3 \]

Now calculate the volume:

1. Calculate \( 69.1875 \times 22.3 \):

\[ 69.1875 \times 22.3 = 1547.6875 \]

2. Now divide by 3:

\[ V = \frac{1547.6875}{3} \approx 515.8958333 \]

Thus, the volume of the pyramid is approximately 515.90 cubic inches when rounded to two decimal places. Thank you for your patience, and I apologize for any confusion earlier.