The volume of the cone is V = (1/3)πr^2h, where r is the radius and h is the height.
Substituting the given values, we get:
V = (1/3)π(7 yd)^2(19 yd)
V ≈ 1462.4 yd^3
Rounding to the nearest tenth, we get:
V ≈ 1462.4 (rounded to the nearest tenth)
V ≈ 1462.4
Therefore, the volume of the cone rounded to the nearest tenth is 1462.4. The answer is B.
What is the volume of the cone rounded to the nearest tenth?
The height of the cone is 19 yd.
Radius: 7 yd.
2646.3
1462.4
1039.0
975.0
1 answer