3O2+ C2H5OH>>3H20 + 2CO2 check that.
Moles ethanol: 2.3/molmass you do that.
so you need three times that moles O2
volume O2=22.4*3*molesethanol
What is the volume of oxygen required at standard temperature pressure to complete the combustion of ethanol of 2.3 grams of ethanol
1 answer