what is the volume of a triangular pyramid with the length of 9 inches, a height of 4 inches, and a width of 6 inches?

1 answer

Ab =

Ab = (W*L)/2 = (6*9)/2 = 27 in^2 = Area
of the base.

V = (Ab*h)/3 = (27*4)/3 = 36 in^3.