What do you mean by
" 800 k/gm^3 than it does in air " ?
The external fluid does not affect the density.
Did you mean to write:
"What is the volume of a metal which weighs 28g less in kerosene does in air, if the density of kerosene is 800 kg/m^3?
That question can be answered.
The metal will certainly sink to the bottom, and there will be an upward buoyancy force of (0.028 kg)*g = 0.274 N. This equals (kerosene density)*g*V, so
V = 0.274/(800*9.8) = 3.5*10^-5 m^3 = 35 cm^3
What is the volume of a metal which weighs 28g less in kerosene and the densty is 800 kgm3 than it does in air
1 answer
1 answer