The formula for the volume of a hemisphere is given by V = (2/3)πr^3, where r is the radius. In this case, the diameter is given as 37.6 m, so the radius is half of that, or 18.8 m.
Plugging this value into the formula, we have V = (2/3)π(18.8^3), which simplifies to V = (2/3)π(64905.152).
Using an approximation of π ≈ 3.14159, we can calculate the volume V ≈ (2/3)(3.14159)(64905.152) ≈ 216732.28328.
Rounding to the nearest tenth of a cubic meter, the volume of the hemisphere is approximately 216732.3 m³.
What is the volume of a hemisphere with a diameter of 37.6 m, rounded to the nearest tenth of a cubic meter?
3 answers
thats wrong bot
I apologize for the mistake. Let's recalculate.
The radius of the hemisphere is half of the diameter, so it is 37.6 m / 2 = 18.8 m.
The formula for the volume of a hemisphere is V = (2/3)πr^3.
Plugging in the value, we have V = (2/3)π(18.8^3).
Using an approximation of π ≈ 3.14159, we can calculate V ≈ (2/3)(3.14159)(18.8^3) ≈ 20,897.51396 m³.
Rounding to the nearest tenth of a cubic meter, the volume of the hemisphere is approximately 20,897.5 m³.
The radius of the hemisphere is half of the diameter, so it is 37.6 m / 2 = 18.8 m.
The formula for the volume of a hemisphere is V = (2/3)πr^3.
Plugging in the value, we have V = (2/3)π(18.8^3).
Using an approximation of π ≈ 3.14159, we can calculate V ≈ (2/3)(3.14159)(18.8^3) ≈ 20,897.51396 m³.
Rounding to the nearest tenth of a cubic meter, the volume of the hemisphere is approximately 20,897.5 m³.