each cube has a volume of (1/3)^3 = 1/27 in^3
so, the total volume is 567/27 = 21 in^3
What is the volume of a box that will hold exactly 567 cubes with 1/3 inch sides? I am somewhat confused on how to solve this. Please help.
5 answers
21
it's 21
21 in^3
idk but i need help in iready