What is the volume of 6M H2SO4 required by the balanced equation to react with the CuO to produce 0.025 moles of copper(ii) sulfate. Report the volume needed BEFORE allowing for excess in milliliters to two significant figures. Don not include units in the answer box.
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CuO + H2SO4 ==> CuSO4 + H2O
You want 0.025 mols CuSO4 so you must have start with 0.025 mols H2SO4 (from the coefficients in the balanced equation).
Then M H2SO4 = mols H2SO4/L H2SO4. You know M and mols, solve for L and convert to mL. I have no idea what "allowing for excess" means in this problem. I suspect you didn't type all of the problem.
You want 0.025 mols CuSO4 so you must have start with 0.025 mols H2SO4 (from the coefficients in the balanced equation).
Then M H2SO4 = mols H2SO4/L H2SO4. You know M and mols, solve for L and convert to mL. I have no idea what "allowing for excess" means in this problem. I suspect you didn't type all of the problem.
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