To calculate the volume of a gas, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (2 atm)
V = volume
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (1C = 274.15 K)
First, we need to find the number of moles of neon gas:
molar mass of neon (Ne) = 20.1797 g/mol
n = mass / molar mass
n = 23g / 20.1797 g/mol ≈ 1.14 mol
Now, we can substitute the values into the ideal gas law equation:
2 atm * V = 1.14 mol * 0.0821 L.atm/mol.K * 274.15 K
2V = 25.14
V ≈ 12.57 L
Therefore, the volume of 23g of neon gas at 1C and a pressure of 2 atm is approximately 12.57 liters.
What is the volume of 23g of neon gas 1C and a pressure of 2 atm
1 answer