To calculate the volume of a gas at zero degrees and 2 atm, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure (2 atm)
V = volume
n = number of moles of gas (1.5 moles)
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (273 K for 0 degrees Celsius)
Let's plug in the values:
(2 atm) * V = (1.5 moles) * (0.0821 L.atm/mol.K) * 273 K
2V = 36.10935
V = 36.10935 / 2
V = 18.054675
Therefore, the volume of 1.5 moles of a gas at zero degrees and 2 atm is approximately 18.05 liters.
What is the volume of 1.5 moles of a gas at zero degrees and 2 arm?
1 answer