What is the volume occupied by 0.738g of xenon gas at STP?

Answer 1

Assuming ideal gas, we use ideal gas law formula:
PV = nRT
where
P = pressure (atm)
V = volume (L)
n = moles
T = absolute temperature (K)
R = universal gas constant = 0.0821 L-atm/mol-K

At Standard Temperature & Pressure (STP), T = 273 K and P = 1 atm.
Xenon has molar mass of 131 g/mol and it isn't diatomic. To get its moles, we just divide the given mass by the molar mass.
PV = nRT
1 * V = (0.738 / 131) * 0.0821 * 273
V = ?

Units in L. Hope this helps~ `u`

Answer 2

0.12626729313