x^2+12x + 36=4+36
(x+6)^2=40
y=(x+6)^2-40 is vertex form.
What is the vertex form of the equation? Show steps
y=-x^2+12x-4
3 answers
y = -x^2+12x-4
= -(x^2-12x)-4
= -(x^2-12x+36)-4+36
= -(x-6)^2 + 32
= -(x^2-12x)-4
= -(x^2-12x+36)-4+36
= -(x-6)^2 + 32
y=x^2-12x+38