What is the value of the range of the function f(x) = x² + 2 for the domain value one-fourth ?

Question

Responses

y = 2
y = 2 - no response given

y = 2one-fourth
y = 2 - image with description: one-fourth - - no response given

y = 2one-eighth
y = 2 - image with description: one-eighth - - incorrect

y = 2Start Fraction 1 over 16 End Fraction
show your work

Answer 1

To find the range of the function f(x) = x^2 + 2 when the domain value is one-fourth, we substitute x = 1/4 into the function:

f(1/4) = (1/4)^2 + 2
f(1/4) = 1/16 + 2
f(1/4) = 17/16

Therefore, the value of the range of the function f(x) = x^2 + 2 for the domain value one-fourth is 17/16.