What is the value of the range of the function f(x) = x² + 2 for the domain value one-fourth ?

Question

(1 point)
Responses

y = 2

y = 2one-fourth

y = 2one-eighth

y = 2Start Fraction 1 over 16 End Fraction

Answer 1

To find the range of the function f(x) = x² + 2 for the domain value of one-fourth, we need to substitute x = 1/4 into the function:

f(1/4) = (1/4)² + 2
= 1/16 + 2
= 1/16 + 32/16
= 33/16

Therefore, the value of the range for the domain value of one-fourth is y = 33/16, or y = 2 1/16.