Nope, however, I'll give you a hint
f(x) = x^2 + 2
Plug in the values...
f(1/4) = (1/4)^2 + 2
Solve the following in order to get your answer.
(1/4)^2 + 2
What is the value of the range of the function f(x)=x^2 + 2 for the domain value 1/4?
A. y=2
B. y=2 1/4***
C. y=2 1/8
D. y=2 1/16
Can anyone check my answer?
1 answer
3 answers