What is the value of the function y = 1 over 8x − 13 when x = −4?

options:

−15
negative 15

−12.5
negative 12.5

−13.5
negative 13.5

−16

1 answer

To find the value of the function \( y = \frac{1}{8x - 13} \) when \( x = -4 \), we first substitute \(-4\) into the function:

\[ y = \frac{1}{8(-4) - 13} \]

Calculating the denominator:

\[ 8(-4) = -32 \]

Now substituting that back in:

\[ y = \frac{1}{-32 - 13} \] \[ y = \frac{1}{-45} \]

Thus, \( y = -\frac{1}{45} \).

Now we can check the options given. However, none of the options provided match the calculated value of \( y \). The answer is:

\(-\frac{1}{45}\), but that is not listed in the options. Thus, it seems there might be an error in the provided options, or in the function given.