What is the value of the function y = 1 over 8x−13 when x=−4?

options:

−15
negative 15

−12.5
negative 12.5

−13.5
negative 13.5

−16

1 answer

To find the value of the function \( y = \frac{1}{8x - 13} \) when \( x = -4 \), we can substitute \(-4\) for \(x\):

\[ y = \frac{1}{8(-4) - 13} \]

Now, calculate \(8(-4)\):

\[ 8(-4) = -32 \]

Now substitute this value back into the equation:

\[ y = \frac{1}{-32 - 13} \]

Next, calculate \(-32 - 13\):

\[ -32 - 13 = -45 \]

So, we have:

\[ y = \frac{1}{-45} \]

This simplifies to:

\[ y = -\frac{1}{45} \]

Now, let's evaluate if \(-\frac{1}{45}\) matches any of the options provided. Since none of the offered options of \(-15\), \(-12.5\), \(-13.5\), or \(-16\) match \(-\frac{1}{45}\), it appears that there may be an error in interpreting the function or the choices available don't correspond to the computed value.

Thus, based on calculations for \( x = -4 \):

\[ y \approx -0.0222 \]

This confirms no given option matches. Please review the function and available choices again!

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