To fill in the missing values in the area model for the expression \( 6(6b - 1) \), we can follow the distributive property of multiplication over addition.
First, let's break down the expression:
\[
6(6b - 1) = 6 \cdot 6b - 6 \cdot 1
\]
This means that:
- The first term (missing value above) will be \( 6 \cdot 6b \)
- The second term (missing value below) will be \( -6 \cdot 1 \)
Thus, we can fill in the area model as follows:
- The left area will represent \( 6 \) (as it is the common factor).
- The right area will represent \( 6b \) for the first term and \( -1 \) for the second term.
The filled area model looks like this:
\[
\begin{array}{|c|c|}
\hline
6 & 6b \
\hline
6 & -6 \
\hline
\end{array}
\]
So, the completed area model corresponds with the factored expression \( 6(6b - 1) \).
Now, if we calculate the total area, we have:
- The area of the first rectangle: \( 6 \cdot 6b = 36b \)
- The area of the second rectangle: \( 6 \cdot (-1) = -6 \)
Thus, the expression expands to:
\[
36b - 6
\]
Therefore, the completed area model is:
\[
6(6b - 1) = 36b - 6
\]