To evaluate the expression \( 6x - y \) with the given values, we need to first determine the value of \( y \) from the equation \( 2y = 2 \).
-
Solve for \( y \): \[ 2y = 2 \ y = \frac{2}{2} \ y = 1 \]
-
Now substitute \( x = 3 \) and \( y = 1 \) into the expression \( 6x - y \): \[ 6x - y = 6(3) - 1 \]
-
Calculate \( 6(3) \): \[ 6(3) = 18 \]
-
Now subtract \( y \): \[ 18 - 1 = 17 \]
Thus, the value of the expression \( 6x - y \) when \( x = 3 \) and \( y = 1 \) is \( \boxed{17} \).