what is the value of (n) ?

(n+3)! = 5040

the prime factorization of 5040 = 2x2x2x2x3x3x5x7

since the ! function involves the multiplication of consecutive integers, it makes sense to arrange these factors so they form consecutive numbers.
I got 2,3,4,5,6, and 7

and sure enough 7!=5040
so (n+3)!=7!
n+3=7 and n=4

An even easier way would be to just try some factorial values. It does not take much to realize that 7!=5040

thanks

i need help on my algebra homework..we are working on radicals and ex. of a question would be..
7*the square root of 2

well thank you..

-carmen