What is the value of f(-6) when f(x)=x2+8x+10

(1 point)
Responses

-4
-4

-2
-2

-6x-38
-6x-38

-74

1 answer

To find the value of \( f(-6) \) when \( f(x) = x^2 + 8x + 10 \), we need to substitute \(-6\) for \(x\) in the function:

\[ f(-6) = (-6)^2 + 8(-6) + 10 \]

Calculating each term:

  1. \((-6)^2 = 36\)
  2. \(8(-6) = -48\)

Now substituting these values into the function:

\[ f(-6) = 36 - 48 + 10 \]

Now, calculate it step by step:

\[ 36 - 48 = -12 \] \[ -12 + 10 = -2 \]

Therefore, the value of \( f(-6) \) is \(-2\).

The correct response is: \(-2\)