What is the value of −12−(−6)

?

9 answers

To solve the expression \(-12 - (-6)\), we can simplify it step by step.

  1. The expression involves subtracting a negative number, which is the same as adding its positive counterpart: \[ -12 - (-6) = -12 + 6 \]

  2. Now, we can perform the addition: \[ -12 + 6 = -6 \]

Thus, the value of \(-12 - (-6)\) is \(\boxed{-6}\).

What is the value of -18.1 + 5?

To calculate \(-18.1 + 5\), you can follow these steps:

  1. Start with \(-18.1\).
  2. Since you're adding a positive number (5), you can think of it as moving to the right on the number line from \(-18.1\).

Calculating the addition:

\[ -18.1 + 5 = -18.1 + 5.0 = -13.1 \]

Thus, the value of \(-18.1 + 5\) is \(\boxed{-13.1}\).

What is the value of −189.987−30.87
?

To compute \(-189.987 - 30.87\), you simply add the two negative numbers together:

\[ -189.987 - 30.87 = -189.987 + (-30.87) \]

Now, you add the absolute values:

\[ 189.987 + 30.87 = 220.857 \]

Therefore, adding the negatives gives:

\[ -189.987 - 30.87 = -220.857 \]

Thus, the value of \(-189.987 - 30.87\) is \(\boxed{-220.857}\).

−1/4+−3/5=
Please enter your answer as a FRACTION. Please do not enter a decimal value.

(1 point)

To add the fractions \(-\frac{1}{4}\) and \(-\frac{3}{5}\), we first need a common denominator. The least common multiple of 4 and 5 is 20.

Now we convert each fraction to have a denominator of 20:

  1. Convert \(-\frac{1}{4}\): \[ -\frac{1}{4} = -\frac{1 \times 5}{4 \times 5} = -\frac{5}{20} \]

  2. Convert \(-\frac{3}{5}\): \[ -\frac{3}{5} = -\frac{3 \times 4}{5 \times 4} = -\frac{12}{20} \]

Now we can add the two fractions: \[ -\frac{5}{20} + -\frac{12}{20} = -\frac{5 + 12}{20} = -\frac{17}{20} \]

Therefore, the value of \(-\frac{1}{4} + -\frac{3}{5}\) is \(\boxed{-\frac{17}{20}}\).

so its 17/20?

No, the correct answer is \(-\frac{17}{20}\).

To clarify:

When adding \(-\frac{1}{4}\) and \(-\frac{3}{5}\), we found that:

\[ -\frac{1}{4} + -\frac{3}{5} = -\frac{17}{20} \]

So, the final answer is \(-\frac{17}{20}\), not \(\frac{17}{20}\). Thank you for your inquiry!