What is the total resistance of the following combination of resistors: 4.0Ω, 6.0Ω, 12.0Ω, and 7.0Ω. The 7Ω resistor is serial, while the 6Ω, 4Ω and 12Ω resistors are parallel.

Answer 1

First, we need to calculate the total resistance of the resistors in parallel:

1/Req = 1/6 + 1/4 + 1/12
1/Req = 2/12 + 3/12 + 1/12
1/Req = 6/12
Req = 12/6
Req = 2Ω

Now, we can find the total resistance of the whole combination by adding the total resistance of the parallel resistors with the serial resistor:

Total Resistance = 2 + 7
Total Resistance = 9Ω

Therefore, the total resistance of the combination of resistors is 9Ω.