What is the total number of nonbonding valence electrons in the "dipolar ion" form of glycine, +NH3CH2COO-?

Answer 1

I count 10.
Draw the H2N-CH2-COOH.
There are 30 electrons. Place those electons with each H of 2, each C of 4, each O as 8 (with a double bond to one C) and 1 unbound pair on N. NOW, move the H of the COOH to the N of the H2N which will give you the dipolar form. Then count the unbound electrons. I count 4 on the C=O oxygen and 6 on the C-O to make 10 total.
Check my work.