0.0200 M CaCl2.
So you have 0.0200 M Ca^2+ and 2*0.0200 M Cl^- and the total is 0.0200 + 0.0400 = 0.0600 M total.
You do the other two the same way. Post your work if you get stuck.
What is the total molar concentration of all the ions in 0.0200 M solutions of the following salts in water?
0.0200 M KCl
0.0200 M CuSO4
0.0200 M CaCl2
2 answers
0.0200 M KCl = 0.0400M (0.0200 M of K + 0.0200 M of Cl = 0.0400M KCl)
0.0200 M CuSO4 = 0.0400M (0.0200 M of Cu + 0.0200 M SO4 = 0.0400M CuSO4)
0.0200 M CaCl2 = 0.0600 M (0.0200 M of Ca + 0.0400 M of Cl = 0.0600 M of CaCl2)
0.0200 M CuSO4 = 0.0400M (0.0200 M of Cu + 0.0200 M SO4 = 0.0400M CuSO4)
0.0200 M CaCl2 = 0.0600 M (0.0200 M of Ca + 0.0400 M of Cl = 0.0600 M of CaCl2)