The molecular should be written:
Sr(OH)2 (aq) + HClO2 (aq) --> Sr(ClO2)2 (aq) + 2H2O (l)
The complete ionic equation would then be:
Sr2+ (aq) + 2OH- (aq) + 2H+ (aq) + 2ClO2-(aq) --> Sr2+ (aq) + 2OH- (aq) + 2ClO2-(aq) + 2H2O (l)
You were close but chlorite ion is ClO2- instead of 2ClO- and since strontium has a 2+ charge, there would have to be two chlorite ions.
Also the net ionic equation is 2OH- (aq) + 2H+ (aq) --> 2H2O (l)
I hope this helps!
If you need any further help, khan academy has some good article. Just look up "complete and net ionic equations".
What is the total ionic and net ionic equation for this aqueous reaction?:
Sr(OH)2(aq) + HClO2 (aq)
-I wrote the molecular as:
Sr(OH)2 (aq) + HClO2 (aq) ---> SrClO2 (aq) + H20 (l)
-Is the Total Ionic:
Sr2+ (aq) + 2OH- (aq) + H+ (aq) + 2ClO- (aq) ---> Sr2+ (aq) + 2ClO-(aq) + H2O (l)
1 answer
2 answers