Write and balance the molecular equation. You've done that. I've added the phases aq for aqueous and s for solid (meaning a ppt)
Ba(NO3)2(aq) + (NH4)2C2O4 (aq)→ Ba(C2O4) (s)+ 2NH4(NO3)(aq)
Separate the aq materials into ions like this but leave the solid since it doesn't dissolve.
Ba^2+(aq) + 2NO3^-(aq) + 2NH4^+(aq) + C2O4^2-(aq) ==> BaC2O4(s) + 2NH4^+(aq) + 2NO3^-(aq)
What you have now is the total ioinic equation. Now cancel the ions common to each side. 2NO3^- is on both sides so cancel. 2NH4^+ is on both sides so cancel. What's left is the net ionic equation.
Ba^2+(aq) + C2O4^2-(aq) ==> BaC2O4(s)
You do the others. Post any follow up questions here to help if you don't understand what I did above.
What is the total iconic equation and net ionic equation of the reaction between barium nitrate and ammonium oxalate Ba(NO3)2 + (NH4)2C2O4 → Ba(C2O4) + 2NH4(NO3)
What is the total iconic equation and net ionic equation of the reaction between calcium nitrate and ammonium oxalate?
Ca(NO3)2 + (NH4COO)2 = Ca(COO)2 + 2NH4NO3
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