using Newtons, kg, meters
water pressure = 1000 kg/m^3*9.8 m/s^2 * 1.5 m = 14,700 N/m^2
so total pressure = 14,700 +100,000 = 114,700 N/m^2
area = pi d^2/4 = pi 4^2/4 = 12.6 m^2
s total force down = 114,700 *12.6
= 1441400 = 1.44*10^6 sure enough
Note, the air also pushes up on the bottom of the pool so things are not as bad as they look
What is the total force on the bottom of a 400-cm-diameter by 1.5-m-deep round wading pool due to the weight of the air and the weight of the water? (Note the pressure contribution from the atmosphere is 1.0 x 10^5 N/m^2, the density of water is 1 g/cm^3, g=9.8m/s^2.)
(Answer: 1.44 x 10^6 N)
1 answer
1 answer