To find the time required for $2500 to amount to $3000 at 6% compounded quarterly, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the resulting amount
P = principal amount (starting amount)
r = interest rate (in decimal form)
n = number of times interest is compounded per year
t = number of years
In this case,
P = $2500
A = $3000
r = 6% = 0.06 (as a decimal)
n = 4 (compounded quarterly)
Let's substitute the known values into the formula and solve for t:
3000 = 2500(1 + 0.06/4)^(4t)
Divide both sides by 2500:
1.2 = (1 + 0.06/4)^(4t)
Take the natural logarithm (ln) of both sides:
ln(1.2) = ln[(1 + 0.06/4)^(4t)]
ln(1.2) = (4t) ln(1 + 0.06/4)
Divide both sides by ln(1 + 0.06/4):
(4t) = ln(1.2) / ln(1 + 0.06/4)
t = [ln(1.2) / ln(1 + 0.06/4)] / 4
Using a calculator, we find:
t ≈ 3.89
Thus, the time required for $2500 to amount to $3000 at 6% compounded quarterly is approximately 3.89 years.
What is the time required for $2500 to amount to $3000 at 6% compounded quarterly
1 answer