What is the theoretical probability of rolling a sum of 6 one roll of two standard number cubes?

Answer 1

There are 36 possible outcomes when rolling two standard number cubes. To find the number of outcomes that result in a sum of 6, we can make a table:

| Cube 1 | Cube 2 | Sum |
|--------|--------|-----|
| 1 | 5 | 6 |
| 2 | 4 | 6 |
| 3 | 3 | 6 |
| 4 | 2 | 6 |
| 5 | 1 | 6 |

There are 5 outcomes that result in a sum of 6. Therefore, the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes is:

$$\frac{\text{Number of outcomes resulting in a sum of 6}}{\text{Total number of possible outcomes}}=\frac{5}{36}\approx0.139$$

So the theoretical probability of rolling a sum of 6 on one roll of two standard number cubes is approximately 0.139 or 13.9%.

Answer 2

are you sure

Answer 3

Yes, I'm sure. The probability of rolling a sum of 6 on one roll of two standard number cubes is 5/36, which is approximately 0.139 or 13.9%.