What is the temperature of an ideal gas whose molecules have an average translational kinetic energy of 3.90 10-20 J?

Question

K

Answer 1

(1/2) m v^2 average = (3/2) k T
k = R/Avagadro's number
= 1.38*10^-23 joules/molecule deg K

3.9 *10^-20 = 1.5 (1.38*10^-23) T

T = 188 K