What is the temperature change when 9.8 g of KNO3( with 34.9 kJ/mol enthaply of solution) is dissolved in 150 g of water? Assume that the specific heat capacity is 4.18 J/K*g. Answer in celcius.
So far I have the Q= ^T*m*s but i don't know what numbers go where and what not.
^T= delta T
KNO3(s) + H2O + heat ==> KNO3(aq)
q = mass x specific heat x deltaT
change 9.8 g KNO3 to mols and calculate q from the 34.9 kJ/mol. Change to J.
Plug that number in for q, mass is mass of water (150 g), specific heat is that of water (4.184 J/g*C) and delta T is the unknown. solve for delta T. Post your work if you get stuck.