1 watt = 1 J/second
2.3 kwh = 2.3E3 x (60 s/min) x (60 min/hr) = ?? J/
??J = mass H2O x specific heat H2o x (Tfinal-Tinitial)
I assume the water has density of 1.00 g/mL wo 29.5 L will have a mass of 29.5 x 1000 to convert to cc = 29500 grams.
What is the temperature change in celsius when 29.5L of water absorbs 2.3 kwh of heat?
1 answer