To find the surface area of the three-dimensional figure, we need to calculate the area of each face and then add them together.
The square base has side lengths of 3 inches, so its area is 3 inches * 3 inches = 9 square inches.
The four congruent triangles each have a base of 3 inches and a height of 8 inches, so the area of each triangle is (1/2) * 3 inches * 8 inches = 12 square inches.
Since there are four triangles, the total area of the triangles is 4 * 12 square inches = 48 square inches.
Therefore, the surface area of the three-dimensional figure is 9 square inches (for the base) + 48 square inches (for the triangles) = 57 square inches.
Therefore, the correct answer is A. 57 square inches.
What is the surface area of the three-dimensional figure represented by this net?
The net pattern has a square base of side lengths 3 inches, 3 inches, 3 inches and 3 inches are attached with four congruent triangles of height 8 inches.
A.
57 square inches
B.
60 square inches
C.
105 square inches
D.
108 square inches
1 answer
9 answers