To calculate the surface area of a square pyramid, we must consider the area of the square base and the area of the four triangular faces.
The area of the square base can be found by squaring the length of one side. In this case, the base length is 10 cm, so the area of the square base is (10 cm)^2 = 100 cm^2.
The area of each triangular face can be found using the formula A = (1/2)bh, where A is the area, b is the base length of the triangle, and h is the height of the triangle. In a square pyramid, all the four triangular faces are congruent, so we only need to calculate the area of one of them.
The triangle has a base length of 10 cm (since it is formed by one side of the square base) and a height of 20 cm (given in the question). Plugging these values into the formula, we find that the area of each triangular face is A = (1/2)(10 cm)(20 cm) = 100 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 100 cm^2 = 400 cm^2.
To find the total surface area, we sum the area of the square base and the triangular faces. In this case, the surface area is 100 cm^2 (square base) + 400 cm^2 (triangular faces) = 500 cm^2.
Therefore, the surface area of a square pyramid with a base length of 10 cm and a slight height of 20 cm is 500 cm^2.
What is the surface area of a square pyramid with a base length of 10 cm and a slight height of 20 cm
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1 answer