What is the surface area of a rectangular prism whose dimensions are 334 dm×412 dm×5 dm in square decimeters?(1 point)

Question

Responses

5818 8 dm2
58 Start Fraction 1 over 8 End Fraction dm squared

8438 dm2
84 Start Fraction 3 over 8 End Fraction dm squared

11614 dm2
116 Start Fraction 1 over 4 End Fraction dm squared

16 dm2

Answer 1

The surface area of a rectangular prism can be calculated as follows:

Surface Area = 2lw + 2lh + 2wh

Where l, w, and h are the dimensions of the rectangular prism.

Given:
l = 334 dm
w = 412 dm
h = 5 dm

Now, plug in these values into the formula:

Surface Area = 2(334)(412) + 2(334)(5) + 2(412)(5)
Surface Area = 2(137888) + 2(1670) + 2(2060)
Surface Area = 275776 + 3340 + 4120
Surface Area = 283236

Therefore, the surface area of the rectangular prism is 283236 square decimeters, which is not one of the provided options.