What is the surface area, in square meters, of a cone with a slant height of 8 meters and a radius of 5 meters? Use 3.14 for pi and round to the nearest tenth, if necessary.(1 point)%0D%0A287.12 square meters

5 answers

To find the surface area of a cone, we need to add the area of the base to the lateral surface area. The formula for the lateral surface area of a cone is given by:

Lateral surface area = π × r × l

where r is the radius and l is the slant height.

Using the given values, the lateral surface area is:

Lateral surface area = 3.14 × 5 × 8 = 125.6 square meters (rounded to the nearest tenth)

The formula for the area of the base of a cone is given by:

Base area = π × r^2

Using the given radius, the base area is:

Base area = 3.14 × 5^2 = 78.5 square meters

Now, we can find the total surface area by adding the lateral surface area and the base area:

Total surface area = Lateral surface area + Base area
= 125.6 + 78.5
= 204.1 square meters

Rounded to the nearest tenth, the surface area of the cone is approximately 204.1 square meters, not 287.12 square meters.
wrong bot
Apologies for the incorrect response.

To find the surface area of a cone, we need to calculate the lateral surface area (including the curved surface area) and the base area.

The formula for the lateral surface area of a cone is:

Lateral surface area = π × r × l

where r is the radius and l is the slant height.

Using the given values, the lateral surface area is:

Lateral surface area = 3.14 × 5 × 8 = 125.6 square meters

The formula for the base area of a cone is:

Base area = π × r^2

Using the given radius, the base area is:

Base area = 3.14 × 5^2 = 78.5 square meters

Now, we can find the total surface area by adding the lateral surface area and the base area:

Total surface area = Lateral surface area + Base area
= 125.6 + 78.5
= 204.1 square meters

Therefore, the correct surface area of the cone is approximately 204.1 square meters. Apologies for any confusion caused.
thank you bot that is correct
You're welcome! I'm glad I could assist you and provide the correct answer. If you have any more questions, feel free to ask.