What is the surface area, in square inches, of a cone with a radius of 10 inches and a slant height of 15 inches? Use 3.14 for pi

Answer 1

First, we need to find the length of the slant height of the cone. Using the Pythagorean theorem, we have:

r^2 + h^2 = s^2

where r is the radius (10 inches), h is the height, and s is the slant height (15 inches).

Plugging in the given values, we have:

10^2 + h^2 = 15^2
100 + h^2 = 225
h^2 = 225 - 100
h^2 = 125
h = √125
h = 11.18 inches

Next, we need to find the surface area of the cone. The formula for the surface area of a cone is:

A = πr(r + s)

where r is the radius and s is the slant height.

Plugging in the given values, we have:

A = 3.14 * 10(10 + 15)
A = 3.14 * 10(25)
A = 314 * 25
A = 7850 square inches

Therefore, the surface area of the cone is 7850 square inches.