To find the sum of the two fractions, we first need to find a common denominator. The least common multiple of (g+1) and (g+2) is (g+1)(g+2). So, we have:
start fraction (1/g+2) + (3/g+1) end fraction
= start fraction (1*(g+1) + 3*(g+2)) / ((g+1)(g+2)) end fraction
= start fraction (g + 1 + 3g + 6) / ((g+1)(g+2)) end fraction
= start fraction (4g + 7) / ((g+1)(g+2)) end fraction
So, the answer is:
C. start fraction 4g plus 7 over left parenthesis g plus 1 right parenthesis left parenthesis g plus 2 right parenthesis end fraction
What is the sum start fraction 1 over g plus 2 end fraction plus start fraction 3 over g plus 1 end fraction ?
A. start fraction 3 over g plus 3 end fraction
B. start fraction g plus 3 over left parenthesis g plus 1 right parenthesis left parenthesis g plus 2 right parenthesis end fraction
C. start fraction 4g plus 7 over left parenthesis g plus 1 right parenthesis left parenthesis g plus 2 right parenthesis end fraction
D. start fraction 2g plus 3 over left parenthesis g plus 1 right parenthesis left parenthesis g plus 2 right parenthesis end fraction
1 answer