No.
You need to change the fractions to equivalent fractions with the common denominator of 6.
4/3 = 8/6
2/3 = 4/6
1/3 = 2/6
What is the sum of the geometric sequence 4/3, 2/3, 1/3, 1/6, ....?
I got 8/3, am I right?
3 answers
This would equal 2 1/2 or 2.50
You want the sum of "all " the terms
an infinite GS
you have a GS, where a = 4/3, r = 1/2
sum(of all the terms) = a/(1-r)
= (4/3)/(1-1/2)
= (4/3)/(1/2)
= 8/3 or 2 2/3
an infinite GS
you have a GS, where a = 4/3, r = 1/2
sum(of all the terms) = a/(1-r)
= (4/3)/(1-1/2)
= (4/3)/(1/2)
= 8/3 or 2 2/3
1 answer