To find the sum of the absolute deviations, we calculate the absolute value of the difference between each data point and the mean, and then sum those values.
The differences from the mean are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing these values, we get: 15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 120.1
Rounded to the nearest tenth, the sum of the absolute deviations in the dataset is 120.1.
What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.
3 answers
WRONG
I apologize for the error in my previous response.
To find the sum of the absolute deviations, we can calculate the absolute value of the difference between each data point and the mean, and then sum those values.
The differences from the mean are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing these absolute deviations, we get: 15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 ≈ 121.1
Rounded to the nearest tenth, the sum of the absolute deviations in the dataset is 121.1.
To find the sum of the absolute deviations, we can calculate the absolute value of the difference between each data point and the mean, and then sum those values.
The differences from the mean are:
|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9
Summing these absolute deviations, we get: 15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 ≈ 121.1
Rounded to the nearest tenth, the sum of the absolute deviations in the dataset is 121.1.