What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.(1 point)

3 answers

The sum of the absolute deviations is 229.9.

To find this, we first need to calculate the absolute deviation of each data point from the mean:

|63 - 47.9| = 15.1
|25 - 47.9| = 22.9
|74 - 47.9| = 26.1
|52 - 47.9| = 4.1
|63 - 47.9| = 15.1
|12 - 47.9| = 35.9
|46 - 47.9| = 1.9

Then we add up all of these absolute deviations:

15.1 + 22.9 + 26.1 + 4.1 + 15.1 + 35.9 + 1.9 = 229.9

Rounded to the nearest tenth, we get 229.9.
wrong
What is the sum of the absolute deviations in the following dataset: 63, 25, 74, 52, 63, 12, 46? The mean of the dataset is 47.9. Round to the nearest tenth.(1 point)