To find the sum of \(2 \frac{1}{5}\) and \(1 \frac{3}{5}\), follow these steps:
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Convert the mixed numbers to improper fractions: \[ 2 \frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{10 + 1}{5} = \frac{11}{5} \] \[ 1 \frac{3}{5} = \frac{1 \times 5 + 3}{5} = \frac{5 + 3}{5} = \frac{8}{5} \]
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Add the two improper fractions: \[ \frac{11}{5} + \frac{8}{5} = \frac{11 + 8}{5} = \frac{19}{5} \]
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Convert the result back to a mixed number: \[ \frac{19}{5} = 3 \frac{4}{5} \]
Therefore, the sum of \(2 \frac{1}{5}\) and \(1 \frac{3}{5}\) is \(3 \frac{4}{5}\).
The correct response is: 3 and 4 fifths.
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