What is the sum (a-1)/(abc³)+(3-b)/(abc³) ?

Answer 1

To find the sum, we first need to combine the two fractions by finding a common denominator.

The common denominator for both fractions is abc^3.

So, the sum becomes:

(a-1)/(abc^3) + (3-b)/(abc^3)
= [(a-1) + (3-b)] / (abc^3)
= (a - 1 + 3 - b) / (abc^3)
= (a + 2 - 1 - b) / (abc^3)
= (a - b + 1) / (abc^3)

Therefore, the sum is (a - b + 1) / (abc^3).